Tkwn-dmwak-mn-ajly < HIGH-QUALITY >

a(1)-5=-4→22=v j(10)-5=5=e l(12)-5=7=g y(25)-5=20=t → vegt

d(4)-3=1=a m(13)-3=10=j w(23)-3=20=t a(1)-3=-2 → wrap 24=x k(11)-3=8=h → ajtxh — not. ? No. But given the time, I notice: mn in the code is likely no in plaintext. If m → n is +1, and n → o is +1, then shift is +1. Check: tkwn +1 = ulxo — not English. So not. Step 9: Let's brute-force one word: ajly If ajly = word ? a→w = -4, j→o = -5? No. tkwn-dmwak-mn-ajly

m(13)-5=8=h n(14)-5=9=i → hi

t(20)-3=17=q k(11)-3=8=h w(23)-3=20=t n(14)-3=11=k → qhtk and n → o is +1