[ \Delta L = \alpha , L_0 , \Delta T ]
ΔL = 1.504 – 1.500 = 0.004 m ΔT = 85 – 15 = 70°C α = ΔL / (L₀ ΔT) = 0.004 / (1.500 × 70) = 3.81 × 10⁻⁵ /°C linear thermal expansion problems and solutions pdf
👉 (Note: On your actual webpage, insert the download link here.) [ \Delta L = \alpha , L_0 , \Delta T ] ΔL = 1
ΔT = 30°C Strain if free = α ΔT = (2.3e-5)(30) = 6.9e-4 But walls prevent expansion → compressive stress: Stress = Y × (α ΔT) = (7.0e10)(6.9e-4) = 4.83 × 10⁷ Pa [ \Delta L = \alpha