Digital Signal Processing Sanjit K Mitra 3rd Edition Solution Manual -

$$H(z) = \frac{1}{1 - 0.5z^{-1}}$$

(b) The maximum and minimum values that can be represented by 12-bit unsigned binary numbers are 4095 and 0, respectively.

3.1 The DFT of the sequence $x[n] = 1, 2, 3, 4$ is: $$H(z) = \frac{1}{1 - 0

3.2 The FFT of the sequence $x[n] = 1, 2, 3, 4$ is:

(b) The odd part of the signal $x[n] = \cos(0.5\pi n)$ is $x_o[n] = 0$. $$H(z) = \frac{1}{1 - 0

$$X[k] = \begin{bmatrix} 10 & -2+j2 & -2 & -2-j2 \end{bmatrix}$$

has a pole at $z = 0.8$.

$$H(z) = 1 + 2z^{-1} + 3z^{-2}$$